Question 393269
 If one painter charges a base price of $250 plus $16/hr 
A(x) = 250+16x
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and another painter charges a base price of $210 plus $18/hr
B(x) = 210+18x
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 how many hours does it take for them to be the same?
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Solve:
A(x)=B(x)
250+16x = 210+18x
2x = 40
x = 20 hrs
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Cheers,
Stan H.
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