Question 391403
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sin\varphi\ =\ \frac{opp}{hyp}]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \cos\varphi\ =\ \frac{adj}{hyp}]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \tan\varphi\ =\ \frac{opp}{adj}]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sec\varphi\ =\ \frac{1}{\cos\varphi}]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \csc\varphi\ =\ \frac{1}{\sin\varphi}]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \cot\varphi\ =\ \frac{1}{\tan\varphi}]

<i><b>opp</b></i> stands for the measure of the side of the triangle opposite the angle.

<i><b>adj</b></i> stands for the measure of the side adjacent to the the angle.

<i><b>hyp</b></i> stands for the measure of the hypotenuse.

John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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