<PRE><B>Question 389177</B>
 How do I determine the values of a if f(x)=3a square x cube - ax +4 and f(2)=6?
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f(x) = 3a^2x^3 - ax + 4
Solve for &quot;a&quot; if y = 6 when x = 2
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6 = 3a^2*2^3 - a*2 + 4
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24a^2 - 2a + 4 = 0
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a = [2 +- sqrt(4-4*24*4)]/(24)
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a = [2 +- sqrt(-380)](24)
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a = [2 +-i19.49]/(24)
etc.
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Cheers,
Stan H.
</PRE>