Question 388286
Simplify,
{{{f(x)=x^3+3x^2+3x+1-x^3+3x^2-3x+1=6x^2+2}}}
In vertex form, that would be,
{{{f(x)=6(x-0)^2+2}}}
with a minimum value of,
{{{highlight(y[min]=2)}}}