Question 384882
 i need to plot the graphs of equations and use the X and Y intercept method, and a check point. Using the X value when solving for the chechpoint. 
4x-3y=12
checkpoint is: 1 
i got for the x intercept (3,0)
i got for the y intercept (0, -4) 
but i am having troubles with the checkpoint (1,?)
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Let x = 1 and solve for "y":
4*1-3y = 12
-3y = 8
y = -8/3
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Checkpoint(1, -8/3)
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Cheers,
Stan H.