Question 382890
7C0 (1/4)^0 (3/4)^7 + 7C1 (1/4)^1 (3/4)^6 + 7C2 (1/4)^2 (3/4)^5 = 


(2187/16384) + (5103/16384) + (5103/16384) = (12393/16384) &#8776; 0.7564