Question 380300
  <pre><font size = 3 color = "indigo"><b>
Hi,
Line perpendicular to the graph of 
3x – 5y = 20  Solving for y to put into the slope-intercept form
3x - 20 = 5y
(2/5)x - 4 = y
Note: the standard slope-intercept form for an equation of a line is y = mx + b  
where m is the slope and b the y-intercept.  
y = (2/5)x - 4 slope of this line is (2/5), line perpendicular to it m = -(5/2}
New line:
 y  = (-5/2)x + b  using ordered pair Pt(-1,0) to solve for b
 0  = -5/2(-1) + b
 -5/2 = b
y = (-5/2)x - 5/2
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(-1, 0,0.3),
graph( 300, 300, -6, 6, -6, 6,(-5/2)x - 5/2,(2/5)x - 4 
 ))}}}