Question 379690
Let x = the numerator of the equivelent fraction.
x/(w^2+w-20)=(w-3)/((w+5)
x/((x+5)(w-4))=(w-3)/(w+5)
x={{{(cross(x+5)(w-4)(w-3))/cross(w+5)}}}
x=(w-4)(w-3)
(w^2-7w+12)/(w^2+w-20) Answer
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Ed