Question 41769
{{{b-2 = 1/(b + 2)}}}
or {{{(b-2)(b+2)=1}}}
or {{{b^2 - 2^2 = 1}}}
or {{{b^2 = 1+4 = 5}}}
Therefore either, {{{b = sqrt(5)}}} or {{{b = -sqrt(5)}}}