Question 41632
if y=x-4 and y=x^2-2x-2 then x^2-2x-2=x-4;
add 4 to both sides:         x^2-2x+2=x
subtract x from both sides:  x^2-3x+2=0
factor x^2-3x+2:             (x-2)(x-1)=0
one of these must equal 0: x-2=0 or x-1=0
                             x=2 or x=1
subsitute for both equations y=(2)-4=-2
                             y=(2)^2-2(2)-2=-2
so x=2 works
then see if x=1 works
subsitute:                   y=(1)-4=-3
                             y=(1)^2-2(1)-2=-3
so x=1 also works therefore x=2 and x=1