Question 375425
1.{{{x+y=6}}}
2.{{{x=y+2}}}
SUbstitute eq. 2 into eq. 1,
{{{(y+2)+y=6}}}
{{{2y+2=6}}}
{{{2y=4}}}
{{{highlight(y=2)}}}
Then from eq. 2,
{{{x=2+2}}}
{{{highlight(x=4)}}}