Question 373884
A positive integer is 11 more than 5 times another. The product is 988. Find the two integers using the quadratic formula.
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let one number be x
other number is 11 more than 5x = 5x+11
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product = 988
x(5x+11)=988
5x^2+11x=988
5x^2+11x-988=0
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solve for roots x1 & x2
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Discriminant = 19881
x1= {{{((-11+sqrt(19881))/10)}}}
x1={{{(-11+141)/10}}}
x1=130/10
x= 13 
the other root will be negative so ignore.
The numbers are 13 & 65
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m.ananth@hotmail.ca