Question 5240
Let x = speed of slower cyclist, A
therefore x+5 = speed of faster cyclist, B.


Both A and B travel for 5 hours
Let A travel distance d, so B must travel distance 175-d.


Right, speed = distance/time, so


A: x = d/5 
--> d = 5x


B: x+5 = (175-d)/5
--> 5(x+5) = 175-d 
--> 5x+25 = 175-d 
--> d = 175 - (5x+25) 
--> d = 175 - 5x - 25 
--> d = 150 - 5x. 


So, equate both these for d to get rid of d, since that is something we are not interested in, so 5x = 150 - 5x


10x = 150
x = 15mph --> speed of A

hence B travels at 20mph


jon.