Question 369653
Parallel lines have identical slopes.
{{{m[1]=m[2]=2/3}}}
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{{{y=(2/3)x+b}}}
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Use the point ({{{-6}}},{{{-1}}}) to solve for {{{b}}}
{{{-1=(2/3)(-6)+b}}}
{{{-1=-4+b}}}
{{{b=3}}}
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{{{highlight(y=(2/3)x+3)}}}