Question 369361
First, put the equation in standard form: {{{x^2-5x+9}}}
Then, note a, b, and c: {{{a=1}}}, {{{b=-5}}}, and{{{c=9}}}
Now, put a, b, and c into the quadratic equation: {{{x = (5 +- sqrt( -5^2-4*1*9 ))/(2*1) }}}
Then, solve: {{{x = (5 +- sqrt( -5^2-4*1*9 ))/(2*1) }}}
{{{x = 5 +- sqrt( 25-36 )/(2)}}}
{{{x = 5 +- sqrt( -9 )/(2)}}}
Because there is a square root of a negative number, there are no real number solutions.