Question 40013
Let number be x.
Its square is therefore {{{x^2}}}


So: a number is subtracted from its square: {{{ x^2 - x }}}
and this equals 2 --> {{{ x^2 - x = 2 }}}


so, {{{ x^2 - x - 2 = 0 }}} is a quadratic to solve.
(x-2)(x+1) = 0
(x-2) = 0 or (x+1) = 0
x=2 or x=-1


these are your 2 possible answers


jon.