Question 355178
Use the common denominator, {{{(2x+3)(x-3)}}}

{{{4/(2x+3)-2/(x-3)=(4(x-3))/((2x+3)(x-3))-(2(2x+3))/((2x+3)(x-3))}}}
{{{4/(2x+3)-2/(x-3)=(4(x-3)-2(2x+3))/((2x+3)(x-3))}}}
{{{4/(2x+3)-2/(x-3)=((4x-12)-(4x+6))/((2x+3)(x-3))}}}
{{{4/(2x+3)-2/(x-3)=highlight((-18)/((2x+3)(x-3)))}}}