Question 354377
(4)/(x^2-4)+(2x)/(x-2)+2/(x+2)=0
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Multiply thru by x^2-4 to get:
4 + 2x(x+2) + 2(x-2) = 0
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4 + 2x^2+4x + 2x-4 = 0
2x^2 + 6x -2 = 0
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x^2 + 3x -1 = 0
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x = [-3 +- sqrt(9 -4*-1)]/2
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x = [-3 +- sqrt(13)]/2
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Cheers,
stan H.