Question 39573
Value #1: x = -3
{{{-x^2 - 5x - 6}}}
{{{-(-3)^2 - 5(-3) - 6}}}
{{{-9 + 15 - 6}}}
{{{0}}}
Value #2: x = -2
{{{-(-2)^2 - 5(-2) - 6}}}
{{{-4 + 10 - 6}}}
{{{0}}}
If you look at the parabola below, the zeroes are at {{{-3}}} and {{{-2}}}.
*[invoke quadratic "x", -1, -5, -6]