Question 347768
{{{log(x,1/9) = -1}}}
logs are exponents. This equation says that the
exponent {{{-1}}} with the base {{{x}}} gives me {{{1/9}}}
I can write it this way:
{{{x^(-1) = 1/9}}}
{{{1/x = 1/9}}}
{{{x = 9}}}