Question 346204
According to the law of exponents,
{{{y^2*y^5=y^(2+5)=y^7}}}
{{{(y^2)^5=y^(2*5)=y^10}}}
In expanded form,
{{{y^2=y*y}}}
{{{y^5=y*y*y*y*y}}}
{{{y^2*y^5=y*y*y*y*y*y*y}}}
While,
{{{y^2=y*y}}}
{{{(y^2)^5= (y*y)*(y*y)*(y*y)*(y*y)*(y*y)}}}
{{{(y^2)^5=y*y*y*y*y*y*y*y*y*y}}}