```Question 345434
x+y=655_x=3y

Move all terms containing variables to the left-hand side of the equation.
x+y=655_x-3y=0

Multiply the first equation by -1 to make the coefficients of x have opposite signs.
-(x+y)=-(655)_x-3y=0

Multiply -1 by the 655 inside the parentheses.
-(x+y)=-655_x-3y=0

Multiply -1 by each term inside the parentheses.
-x-y=-655_x-3y=0

Add the two equations together to eliminate x from the system.
x-3y=0_<U>- x-y=-655<u>_  -4y=-655

Divide each term in the equation by -4.
y=(655)/(4)

Substitute the value found for y into the original equation to solve for x.
-x-((655)/(4))=-655

Multiply -1 by each term inside the parentheses.
-x-(655)/(4)=-655

Move all terms not containing x to the right-hand side of the equation.
-x=-(1965)/(4)

Multiply -x by -1 to get x.
x=-(1965)/(4)*-1

Divide each term in the equation by -1.
x=(1965)/(4)

This is the final solution to the independent system of equations.
y=(655)/(4)_x=(1965)/(4)

(655)/(4)

The approximate value of (655)/(4) is 163.75.
\$163.75

(1965)/(4)

The approximate value of (1965)/((4)) is 491.25.
491.25

491.25+163.75

To check the answers of 163.75 AND 491.25:

Add 163.75 to 491.25 to get 655.
655```