Question 340205
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ =\ \frac{8}{x}\ +\ 15]

Multiply both sides by *[tex \Large x], collect terms on the left, and factor:

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2\ =\ 8\ +\ 15x]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2\ -\ 15x\ -\ 8\ =\ 0]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (2x\ +\ 1)(x\ -\ 8)\ =\ 0]

Finish solving for *[tex \Large x], and then discard the negative root (you are looking for a natural number if you remember)

John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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