Question 337706
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The instantaneous velocity of a falling object at time *[tex \Large t] is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ v(t)\ =\ -gt\ +\ v_o]


where *[tex \Large g] is the acceleration due to gravity and *[tex \Large v_o] is the initial velocity, and positive values are upwards.  Even though you didn't specify, I'm going to assume that your cliff is located on the surface of the planet Earth -- hence *[tex \Large g\ =\ 32\text{ ft/sec^2}]


Note that 30 miles per hour is 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 30\ \times\ 1.467\ =\ 44] feet per second.



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -44\ =\ -32t\ +\ 0]


Just solve for *[tex \Large t]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<img src="http://www.evolvefish.com/fish/media/E-FlyingSpaghettiEmblem.gif">
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