Question 335234
1. compute the probability that "ONE" person at random has an IQ of 110 or above the mean is 100 and the deviation is 15
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Unfortunately, we cannot do this without knowing the type of distribution this person comes from.
If we assume that the underlying distribution is Normal, we can continue.
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{{{P(X>=110, mu=100, sigma=15)}}}={{{P(Z>=(110-100)/15)=P(Z>=0.667)=0.252}}}
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2. Now, to compute the probability of "TWO" people at random both having an IQ of 110 or above the mean is 100 and the deviation is 15
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We need to know if the two people are independent in terms of their IQ, 
if they can be considered independent then 
P(two people having an IQ>110)= {{{0.252^2}}}=0.0635