Question 333482
A. two consecutive integers :  x and x+1

B. The product of two consecutive integers   x*(x+1)
C. 4 less than four times their sum:  4[x+(x+1)]-4
D. x*(x+1)=4[x+(x+1)]-4  (equate the sides)
E. x^2+x=4(2x+1)-4      (simplify the equation)
F. x^2 +x=8x+4-4=8x    (simplify the equation)
G. x^2=-x+8x=7x        (subtract x from both sides)
H. x=7               (divide both sides by x)
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check solution by substituting x=7 back in original equation
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x*(x+1)=4[x+(x+1)]-4 
7*(7+1)=4*(7+(7+1))-4
7*8=4*(15)-4
56=60-4=56