Question 333240
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There are 6 times 6 = 36 one unit by one unit squares

There are 5 times 5 = 25 two unit by two unit squares

There are 4 times 4 = 16 three unit by three unit squares

There are 3 times 3 = 9 four unit by four unit squares

There are 2 times 2 = 4 five unit by five unit squares

There is 1 times 1 = 1 six unit by six unit square.

You  can either add those up or use the sum of squares formula:

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sum_{i=1}^n\ i^2\ =\ \frac{n(n+1)(2n+1)}{6}]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sum_{i=1}^6\ i^2\ =\ \frac{6(6+1)(2(6)+1)}{6}]

The arithmetic is yours to do.

John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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