<PRE><B>Question 328296</B>
The chief of police for small town USA notice that, not including himself,
 3/5 of his police force carries firearms.
If he include himself, 5/8 of his force carries firearms.
 How many people on his force do not carry firearms?
:
Originally then, 2/5 did not carry guns
Later then, 3/8 did not carry guns
:
Let x = total on the police force not counting the chief 
:
No. not carrying guns remains unchanged, so we have:
{{{2/5}}}x = {{{3/8}}}(x+1)
Multiply both sides by 40, results
8(2)x = 5(3(x+1))
16x = 15x + 15
16x - 15x = 15
x = 15 total on the police force
then
{{{2/5}}}*15 = 6 did not carry guns
:
Confirm solution
{{{3/8}}}*(15+1) = 6 also</PRE>