Question 326849
 solve an inequality: 
x/x+20>2/x+8
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Find the boundary value(s) for the inequality by
solving the equalty.
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x/(x+20) = 2/(x+8)
x^2+8x = 2x+40
x^2 + 6x - 40 = 0
(x^2+10x-4x-40) = 0
(x+10)(x-4) = 0
x = -10 or x = 4
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Draw and number line and plot x = -10 and x = 4  on the line.
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Check a test value from each of the resulting 
three number-line intervals to see where the
inequality solutions lie.
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x/x+20>2/x+8
Check x = -15:
-15/5 > 2/-7 false
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Check x = 0:
0/20> 2/8 false
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Check x = 5
5/25 > 2/13 true
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Solutions for the inequality in (4,+inf)
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Cheers,
Stan H.
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