Question 323458
It's an equation in x.
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log(5-3x)+log(5+3x)=log(16x^2)
{{{log((5-3x)*(5+3x)) = log(16x^2)}}}
{{{log(25 - 9x^2) = log(16x^2)}}}
{{{25 - 9x^2 = 16x^2}}}
{{{25 = 25x^2}}}
{{{x^2 = 1}}}
x = ± 1