Question 316011


First let's find the slope of the line through the points *[Tex \LARGE \left(8,1\right)] and *[Tex \LARGE \left(8,9\right)]



Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(8,1\right)]. So this means that {{{x[1]=8}}} and {{{y[1]=1}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(8,9\right)].  So this means that {{{x[2]=8}}} and {{{y[2]=9}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(9-1)/(8-8)}}} Plug in {{{y[2]=9}}}, {{{y[1]=1}}}, {{{x[2]=8}}}, and {{{x[1]=8}}}



{{{m=(8)/(8-8)}}} Subtract {{{1}}} from {{{9}}} to get {{{8}}}



{{{m=(8)/(0)}}} Subtract {{{8}}} from {{{8}}} to get {{{0}}}



Remember, you <b>cannot</b> divide by zero. So this means that the slope is undefined.



Since the slope is undefined, this means that the equation of the line through the points *[Tex \LARGE \left(8,1\right)] and *[Tex \LARGE \left(8,9\right)] is {{{x=8}}} (since both points have the x coordinate of 8)