Question 315126
{{{k(x)=x-12 }}}


{{{k(0)= 0-12= -12}}}

{{{k(-20)= -20-12= -32}}}

{{{k(4)=4-12= -8}}}

{{{K(2)=2-12= -10}}}

{{{K(c+2)=(c+2)^2 - 12 = c^2 + 4c - 8}}}