Question 35387
(x^-1+y^-1)/(x^-1y)
I cancelled out the x^-1, which left me with y^-1/y, which I think is (1/y)/(y)

Don't cancel terms; x^-1 is a term in the 1st parentheses.

[(1/x)+(1/y)]/(y/x)
[(x+y)/(xy)]*(x/y)
(x+y)/y^2
Cheers,
Stan H.