Question 299768
{{{7x^2 + 11x - 30}}}
Use the quadratic formula
 {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{a = 7}}}
{{{b = 11}}}
{{{c = -30}}}
 {{{x = (-11 +- sqrt( 11^2-4*7*(-30) ))/(2*7) }}}
 {{{x = (-11 +- sqrt( 121 + 840 ))/14 }}}
{{{x = (-11 +- sqrt(961))/14 }}}
{{{x = (-11 + 31)/14}}}
{{{x = 20/14}}}
{{{x = 10/7}}}
and, also
{{{x = (-11 - 31)/14}}}
{{{x = -42/14}}}
{{{x = -3}}}
The factors are:
{{{(x - 10/7)*(x - (-3)) = 0}}}
{{{(x - 10/7)*(x + 3) = 0}}}
check:
Multiplying these, I get
{{{x^2 - (10/7)*x + 3x - 30/7 = 0}}}
Multiply both sides by {{{7}}}
{{{7x^2 - 10x + 21x - 30 = 0}}}
{{{7x^2 + 11x - 30 = 0}}}
OK