Question 298566
An object's altitude, in meters, is given by the polynomial h + vt - 9.8t2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and t is the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 150 meters tall. If the initial speed is 35 meters per second, how high above the ground will the pebble be after 3 seconds? Round results to the nearest tenth of a meter. 
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A pebble is not a rocket.
{{{h(t) = -9.8t^2 + vt + h}}}
h(3) = -9.8*9 + 35*3 + 150
h(3) = 166.8 meters (not rounded)