Question 287740
{{{y = A*e^(kx)}}}
(-2,-10)
(1) {{{-10 = A*e^(k*(-2))}}}
(-1,-4)
(2) {{{-4 = A*e^(k*(-1))}}}
Solve both equations for {{{A}}}
(1) {{{A = -10*e^(2k)}}}
(2) {{{A = -4*e^k}}}
so,
{{{-10*e^(2k) = -4*e^k}}}
{{{e^(2k)/e^k = 2/5}}}
{{{(e^k)^2/e^k = 2/5}}}
{{{e^k = 2/5}}}
{{{k = ln(.4)}}}
{{{k = -.92}}}
and
(2) {{{A = -4*e^k}}}
{{{A = -4*e^(-.92)}}}
{{{A = -4*.4}}}
{{{A = -1.6}}}