Question 34183
(3+2i)/(1+2i)-1/(1-2i)={(3+2i)(1-2i)/(1-2i)(1+2i)} -{1(1+2i)/(1+2i)(1-2i)}
={(3-6i+2i-4i^2)/(1-4i^2)} - {(1+2i)/(1-4i^2)}
={(7-4i)/5}- {(1+2i)/5}=(7-4i-1-2i)/5=(6-6i)/5=6(1-i)/5