Question 274402
 Here's my problem... 
The difference of the squares of two consecutive negative integers is 9. Find the integers. 
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1st: x
2nd: x+1
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Equation:
(x+1)^2-x^2 = 9
x^2 + 2x + 1 - x^2 = 9
2x + 1 = 9
2x = 8
x = 4
x+1 = 5
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Cheers,
stan H.