Question 272323
0.5^x-0.25=4 I added 0.25 to both sides so now I have 
:
0.5^x = 4.25 
At this point you want to find the log of both sides
{{{log(.5^x) = log(4.25)}}}
The log equiv of exponents
{{{x*log(.5) = log(4.25)}}}
divide both sides by log(.5)
x = {{{log(4.25)/log(.5)}}}
on a calc
x = -2.087
;
:
Check solution on a calc:
 enter .5^-2.087, results: 4.248 ~ 4.25, confirms our solution