Question 267789
(2x^3y/8x^-2y^2)^-2
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The "negative" in the exponent tells you to invert.
The 2 in the exponent tells you to square each factor
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1st simplify inside the parenthesis to get:
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(x^5/4y)^-2
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invert to get:
(4y/x^5)^2
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Square to get:
(16y^2/x^10)
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Cheers,
Stan H.