Question 33217
3{{{x^2}}}-4x-5=0 
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
a = 3 ;b = -4; c = -5
{{{x = (-(-4) +- sqrt( (-4)^2-4*(3)*(-5) ))/(2*3) }}} 
{{{x = (4) +- sqrt( 16+60 ))/(2*3) }}} 
{{{x = (4 +- sqrt( 76 ))/6}}} 
{{{x = (4 +- sqrt(4*19))/6 }}} 
{{{x = (4 +- 2sqrt(19))/6 }}}
{{{x = (2 +- sqrt(19))/3 }}}