Question 33015
6000x-2000y+136000=0 (4< x < 18)
where x=4 corresponds to 1994
<P>
It reduces to y=3x+68.
<P>
x=4,y=3(4)+68=12+68=80
x=5,y=3(5)+68=15+68=83
x=6,y=86
x=7,y=89
x=8,y=92------------->(a)
x=9,y=95
x=10,y=98
x=11,y=101
x=12,y=104
x=13,y=107
x=14,y=110----------->(b)
x=15,y=113
x=16,y=116
x=17,y=119
x=18,y=122
<P>
If you substitute x=0,we get y=68.Multiply this by 1000 and we get a credible figure,considering it as 1990. Then for x=18,y=122 ie in the year 2008, a figure of $122000 seems to make sense.
<P>
That would make 1998 and 2004 your answers,though of course we have no logical reasoning to back this up.
<P>
If this is a valid question,and you do manage to solve this,drop a mail at:
xcentaur[at]hotmail[dot]com
Hope this helps,
xC