Question 256168
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Use Pythagoras to find the measure of the hypotenuse of a right triangle given the measures of the two legs.

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c\ =\ \sqrt{a^2\ +\ b^2}]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c\ =\ \sqrt{(20)^2\ +\ (48)^2}]

The arithmetic, as usual, is yours to do.  Of course, you could also recognize that 20 is 5 times 4 and 48 is 12 times 4, and recall that 5, 12, and 13 is a Pythagorean Triple hence the hypotenuse of your triangle must be 13 times 4.

John
*[tex \LARGE e^{i\pi} + 1 = 0]
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