Question 254605
Let x be smaller number and y = larger number
We have
(i) {{{x + y = 48}}}
(ii) {{{2y = x + 6}}}
Solve (i) for x to get
(iii) {{{x = 48 - y}}}
By substitution, we get
(iv) 2y = 48-y + 6}}}
and then
{{{3y = 54}}}
{{{y = 18}}}
Now, we find x as
{{{x = 30}}}