Question 252753ms.berger has two investments. one has 8% annual interest rat, and the other investment has 9.5%. she invests 37,000, part at 8% and the rest at 9.5% annual interest rate. the 9.5% investment provides $452.5 more income than 8% investment. how much is invested at each rate? : Let x = amt invested at 9.5% The total was given as 37000, therefore (37000-x) = amt invested at 8% : Int at 9.5% - Int at 8% = $452.5 .095x - .08(37000-x) = 452.50 .095x - 2960 + .08x = 452.50 .095x + .08x = 452.50 + 2960 .175x = 3412.5 x = {{{3412.5/.175}}} x = $19,500 invested at 9.5% : I'll let you find how much invested at 8%