Question 252615
The age of Kenny = 10
Let the age of Cindy be x
Janet is ten years less than twice of cindy age 
The the age of Janet = 2x-10
Michelle is 5 years younger than cindy 
The the age of Michelle = x-5
Given, the ratio of janets age equal s the ratio of michelles age to kenny's age 
             2x-10   = (x-5)/10
             20x-100 = x-5
             20x-x   = 100-5 
                19x  = 95
                  x  = 95/19
                  x  = 5
Therefore the age of Cindy = 5
          the age of Janet = 2*5-10 = 0
          the age of Michelle= x-5 = 5-5 = 0