Question 245000
Let {{{y=log(2,(x^5))}}}. Now swap x and y to get {{{x=log(2,(y^5))}}}. The goal here is to solve for y.



{{{x=log(2,(y^5))}}} Start with the given equation.



{{{2^x=y^5}}} Convert to exponential form.



{{{root(5,2^x)=y}}} Take the 5th root of both sides to isolate 'y'



So the inverse is {{{root(5,2^x)}}}