<PRE><B>Question 240840</B>
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The given equation is already in slope-intercept form, so you can determine the slope of the given line by inspection of the coefficient on *[tex \Large x].


Use the fact that perpendicular lines have slopes that are negative reciprocals of each other, that is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1 \perp L_2 \ \ \Leftrightarrow\ \ m_1 = -\frac{1}{m_2} \text{ and } m_1, m_2 \neq 0]


to determine the slope of the desired line.


Now use the point-slope form of the equation of a line to write an equation of the desired line, that is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1 = m(x\ -\ x_1)]


where *[tex \Large \left(x_1,y_1\right)] is the given point and *[tex \Large m] is the slope you determined in the previous step.


You should ask your instructor or check for any instructions in your text as to the required final form of your answer such as slope-intercept or standard form.


Unfortunately, I cannot answer your question exactly as you stated it.  One cannot find &lt;b&gt;&lt;i&gt;the&lt;/i&gt;&lt;/b&gt; equation of a line.  That is because for any given set of ordered pairs that describe a straight line in a plane, there are an infinite number of equations that describe the relationship.  The best anyone can ever do is provide &lt;b&gt;&lt;i&gt;an&lt;/i&gt;&lt;/b&gt; equation of a line.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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