Question 239968
(t-3)^2=8 
t^2-6t+9=8
t^2-6t+9-8=0
t^2-6t+1=0
{{{t = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
t=(6+-sqrt[-6^2-4*1*1])/2*1
t=(6+-sqrt[36-4])/2
t=(6+-sqrt32)/2
t=(6+-5.6568)/2
t=11.6568/2
t=5.828 ans.
t=(6-5.6568)/2
t=.3432/2
t=.1716 ans.