<PRE><B>Question 237830</B>
Ten quarters dated 1990-1999 are tossed. What is the probability of the following
a) tails occurring on 1991 quarter only
# of ways to succeed: 1
# of possible outcomes 2^10 = 1024
P(tail on 1991 only) = 1/1024
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(b) tails on all 10 quarters 
(1/2)^10 = 1/1024
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c) exactly 4 tails 
10C4*(1/2)^4*(1/2)^6 = 210/1024
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(d) at least 3 tails
1 - binomcdf(10,0.4,2) = 0.9453
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Cheers,
Stan H.
</PRE>